cb661a42f8
Currently we're reverse sorting with a simple sort, this sadly puts newer released (antalope, bobcat) at the end of the list. Add a key function that has context around our release names and release ids to sort "2024.1/cantaloupe"[1] at the top. [1] As of now the c name isn't selected cantaloupe is my placeholder Change-Id: Ie7a9ffcdbe6a28cd2a80289ec06259ec869d306f
56 lines
2.5 KiB
Python
56 lines
2.5 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License"); you may
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# not use this file except in compliance with the License. You may obtain
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# a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
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# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
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# License for the specific language governing permissions and limitations
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# under the License.
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_series_data = [
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["austin", "bexar", "cactus", "diablo", "essex", "folsom", "grizzly",
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"havana", "icehouse", "juno", "kilo", "liberty", "mitaka", "newton",
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"ocata", "pike", "queens", "rocky", "stein", "train", "ussuri",
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"victoria", "wallaby", "xena", "yoga", "zed"],
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# ["antelope", bobcat, etc etc etc],`
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]
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def keyfunc(series_name):
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assert series_name.isascii()
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# NOTE(tonyb): Create a private copy to avoid mutating input variable
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_series_name = series_name.lower()
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# This for/else statement looks for a series_name in series_data. If it
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# is found stop looking (via break), because we have all the information
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# we need. If the series name isn't found, i.e a run through the entire
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# series_data list-of-lists, the 'else' clause will be executed to do our
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# best to deduce the sort key from there.
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for series_nr, series_names in enumerate(_series_data):
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if _series_name in series_names:
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series_idx = series_names.index(_series_name)
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break
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else:
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if _series_name[0].isalpha():
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series_nr += 1
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series_idx = ord(_series_name[0]) - ord("a")
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elif _series_name[0].isdigit():
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(year, release) = map(int, _series_name.split("."))
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# This arithmetic comes from the fact that we started using
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# year.release naming scheme, after we completed a full list
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# of the alphabet.
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# This happened with the 2023.1 release. To date it's two
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# releases per year. If that changes this code will need to
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# be updated.
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# Releases "austin" -> "zed" are 0 -> 25 so 2023.1 is the 26th
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# OpenStack release
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(series_nr, series_idx) = \
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divmod(26 + ((year - 2023) * 2 + (release - 1)), 26)
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else:
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assert False
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# TODO(tonyb): Do we want to switch this to aa_austin, ba_2023.1 to force
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# a stable sort order
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return series_nr * 26 + series_idx
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